Convolution of f(t) and g(t) denoted (f∗g)(t) is
f∗g=g∗f
f∗(g+h)=(f∗g)+(f∗h)
(f∗g)∗h=f∗(g∗h)
f∗0=0
If f(t) and g(t) are piecewise continuous and of exponential order for t≥0, then so is (f∗g)(t) and